1.

The latent heat of vaporization of a liquid at 500K and atm pressure is 10 kcal/mol. What will bethe change in internal energy (AE) of 3 moles of liquid at the same temperature?

Answer»

3H2O(l)→3H2O(g)3H2O(l)→3H2O(g)

Δng=3Δng=3

ΔE=ΔH−ΔngRTΔE=ΔH−ΔngRT

=3×10−3×500×0.002=27Kcal=3×10−3×500×0.002=27Kcal


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