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The lateral faces of a square pyramid are equilateral triangles Lateral, edge = 20 cm a. Calculate the slant height b. Find its surface area. C. Find its volume. |
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Answer» a. Slant height = 10 √3 cm b. Lateral surface area = \(20^2+4\times\frac{1}{2}\times20\times10\sqrt{3}\) = 400 + \(400\sqrt{3}\) = 400(1 + \(\sqrt{3}\)) cm2 c. Height = \(\sqrt{(10\sqrt{3})^2-10^2}\) = \(10\sqrt{2}\) cm Volume = \(\frac{1}{3}400\times10\sqrt{2}\) = \(4000\frac{\sqrt{2}}{3}\) cm3 |
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