1.

The LCM of two given numbers is 6 times the HCF of the numbers. If the smaller of the two numbers is 6, then the other numbers is1). 152). 83). 94). 12

Answer»

Let the other number be X

Now

LCM × HCF = Product if TWO numbers

As LCM = 6 × HCF

∴ 6 × HCF × HCF = 6 × X

∴ HCF2 = X

Now as HCF is SQUARE root of other number

∴ From options we can say that the answer is 9

We can also check that the LCM of 9 and 6 is 18 and HCF of 9 and 6 is 3

Hence LCM = 6 × HCF


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