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The least count of a screw gauge is `0.005mm` and it has `100` equal divisions on its head scale. Then the distance between two consecutive threads on its screw isA. `0.5mm`B. `0.05mm`C. `0.01mm`D. `0.1mm` |
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Answer» Correct Answer - A `d=0.005xx100=0.05mm` |
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