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The least count of a stop watch is `(1//5)s`. The time 20 oscillations of a pendulum is measured to be `25 s`. The maximum percentage error in this measurement is |
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Answer» Error in measuring 25 s `= (1)/(5) s = 0.2` sec. `" "therefore ` percentage error = `(0.2)/(25)xx 100= 0.8` % The final absolute error in this type of questions is taken to be equal to the least count of the measurement intrument. |
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