The least count of stop watch is 0.5s. The time of 40 oscillation of the pendulum is found to be 40s. The percentage error in the measurement of time period is ……………… %

The least count of stop watch is 0.5s. The time of 40 oscillation of t

1.	The least count of stop watch is 0.5s. The time of 40 oscillation of the pendulum is found to be 40s. The percentage error in the measurement of time period is ……………… %
Answer» <html><body><p>0.75<br/>0.5<br/>1.25<br/>0.25</p>Solution :`"Least <a href="https://interviewquestions.tuteehub.com/tag/count-936718" style="font-weight:bold;" target="_blank" title="Click to know more about COUNT">COUNT</a> = 0.5a"` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/deltat-2053483" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAT">DELTAT</a>=0.5a` <br/> `T=<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>` <br/> `%" <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> "=(DeltaT)/(T)xx100` <br/> `=(0.5)/(40)xx100=(<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>)/(40)=1.25`</body></html>