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The least count of the main scale of a screw gauge is 1mm. The minimum number of divisions on its circular scale required to measure 5mm diameter of a wire is : (1) 100 (2) 200 (3) 50 (4) 500 |
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Answer» The correct option (2) 200 Explanation: 1C.S.d = 5 x 10-6 = (1 x 10-3)/N N = 1000/5 = 200 |
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