InterviewSolution
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InterviewSolution
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The length and breadth of a rectangle are `( 5.7 +- 0.1 ) cm and ( 3.4 +- 0.2 ) cm`, respectively calculate the area of rectangle with error limits. |
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Answer» Correct Answer - `( 19 +- 1.5) cm^(2)` `A = l b = 5.7 xx 3.4 = 19.38 cm^(2) ~ 19 cm^(2)` ( two significant figures) `(Delta A )/( A) = (Delta l )/( l) + ( Delta b)/(b) rArr Delta A = ((0.1)/(5.7) + (0.2)/(3.4)) ( 19.38)` `Delta A = 1.48 = 1.48 ~ 1.5` ( two significant figures) So area `= ( 19 +- 1.5) cm^(2)` |
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