The length breadth and thickness of a metal sheet are 4.234 m, 1.005 m – InterviewSolution

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1.	The length breadth and thickness of a metal sheet are 4.234 m, 1.005 m and 2.01 cm respectively. Given the area and volume of the sheet to correct number of significant figure.
Answer» Here, length I = 4.234 m, breadth b = 1.005m, thickness, `t = 2.01 cm = 2.01xx10^(-2)m` Area of the sheet = `2 (lxxb + bxxt + +txxl) = 2(4.234xx1.005 + 1.005 xx0.0201 + 0.0201 xx 4.234)` `= 2 (4.3604739) = 8.7209478 m^2` As area can contain a maximum of three significant digits, therefore, rounding off, we get `Area = 8.72 m^2` Also, volume = `lxxbxxt` `V = 4.234xx1.005xx0.0201 = 0.0855289 = 0.0855 m^3` ("containing three singinficant figures")`

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