1.

The length of a metal rod at 0^(@)C is 0.5m. When it is heated, its length increases, by 2.7 mm.The final temperature of the rod is (coefficient of linear expansion of the metal =90xx10^(-6)//^(@)C)……………. .

Answer»

`20^(@)C`
`30^(@)C`
`40^(@)C`
`60^(@)C`

Solution :`l_(t)=l_(0)(1+alphat)`
`therefore""t=(l_(t)-l_(0))/(l_(0)alpha)=(2.7xx10^(-3))/(0.5xx90xx10^(-6)), t=60^(@)`


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