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The length of a metal wire is l_(1) when the tension in it is T_(1) and is l_(2) when the tension is T_(2). The natural length of the wire is: |
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Answer» SOLUTION :`"From LENGTH expansion equation "(DeltaL)/(L)=alpha_(L)DeltaT` `"From Area expansion equation, "((DeltaV)/(V_(o)))=alpha_(A)DeltaT` But `alpha_(A)=2alpha_(L)`, therefore, `(DELTAA)/(A_(o))=2alpha_(A)DeltaT=2(DeltaL)/(L)` Percentage CHANGE `=(DeltaA)/(A_(o))xx100=2((DeltaL)/(L)xx100)=2xx1` Percentage change `=2%` |
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