1.

The length of a metal wire is l_(1) when the tension in it is T_(1) and is l_(2) when the tension is T_(2). The natural length of the wire is:

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SOLUTION :`"From LENGTH expansion equation "(DeltaL)/(L)=alpha_(L)DeltaT`
`"From Area expansion equation, "((DeltaV)/(V_(o)))=alpha_(A)DeltaT`
But `alpha_(A)=2alpha_(L)`, therefore, `(DELTAA)/(A_(o))=2alpha_(A)DeltaT=2(DeltaL)/(L)`
Percentage CHANGE `=(DeltaA)/(A_(o))xx100=2((DeltaL)/(L)xx100)=2xx1`
Percentage change `=2%`


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