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The length of a needle floating on water is `2.5 cm`. The minimum force in addition to its weight needed to lift the needle above the surface of water will be (surface tension of water is `0.072 N//m`)A. `3.6xx10^(-3)N`B. `10^(-2)N`C. `9xx10^(-4)N`D. `6xx10^(-4)N` |
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Answer» Correct Answer - A Surface tension force `F=Sxx2l=0.072xx2xx2.5/100=3.6xx10^(-3)N` |
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