The length of a rectangle is (7/10) of its width. If the area of recta

1.	The length of a rectangle is (7/10) of its width. If the area of rectangle is 1750cm2, then find the perimeter.1. 150 cm2. 160 cm3. 170 cm4. 140 cm
Answer» Correct Answer - Option 3 : 170 cm Given Length = (7/10) × breadth Concept Area of rectangle = length × breadth Perimeter of rectangle = 2(length + breadth) Calculation Let the breadth of a rectangle is x cm So, length = (7/10)x Area of rectangle = 1750cm² (7/10)x × x = 1750 ⇒ x²= (1750) × (10)/7 ⇒ x²= 2500 ⇒ x = 50 cm Perimeter of rectangle = 2[(7/10) × 50 + 50] ⇒ 2(85) ⇒ 170 cm ∴ The perimeter of rectangle is 170 cm

The length of a rectangle is (7/10) of its width. If the area of rectangle is 1750cm2, then find the perimeter.1. 150 cm2. 160 cm3. 170 cm4. 140 cm

Answer» Correct Answer - Option 3 : 170 cm

Given

Length = (7/10) × breadth

Concept

Area of rectangle = length × breadth

Perimeter of rectangle = 2(length + breadth)

Calculation

Let the breadth of a rectangle is x cm

So, length = (7/10)x

Area of rectangle = 1750cm²

(7/10)x × x = 1750

⇒ x²= (1750) × (10)/7

⇒ x²= 2500

⇒ x = 50 cm

Perimeter of rectangle = 2[(7/10) × 50 + 50]

⇒ 2(85)

⇒ 170 cm

∴ The perimeter of rectangle is 170 cm

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The length of a rectangle is (7/10) of its width. If the area of rectangle is 1750cm2, then find the perimeter.1. 150 cm2. 160 cm3. 170 cm4. 140 cm

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