The length of a rectangle is five meters more than twice of its breadt

1.	The length of a rectangle is five meters more than twice of its breadth. If the perimeter is 148 meter, then find the length and breadth of the rectangle.
Answer» Let the breadth of the rectangle = x, length of a rectangle is five more than twice of its breadth. Then, length of the rectangle = 2x + 5 Perimeter of the rectangle = 148m 2 (Length + Breadth) = 148 ⇒ 2(2x + 5 + x) = 148 ⇒ 2(3x + 5) = 148 ⇒ 6x + 10 = 148 ⇒ 6x = 148 – 10 ⇒ 6x = 138 ⇒ x = 138/6 ⇒ x = 23 ∴ Breadth of rectangle = 23 m Length of the rectangle = 2x + 5 = (2 × 23) + 5 = 46 + 5 = 51 m Check: Length = 51 m, Breadth = 23 m Perimeter = 2(l + b) = 2(51 + 23) = 2(74) = 148 m Hence Verified.

The length of a rectangle is five meters more than twice of its breadth. If the perimeter is 148 meter, then find the length and breadth of the rectangle.

Answer»

Let the breadth of the rectangle = x,

length of a rectangle is five more than twice of its breadth.

Then, length of the rectangle = 2x + 5

Perimeter of the rectangle = 148m 2 (Length + Breadth) = 148

⇒ 2(2x + 5 + x) = 148

⇒ 2(3x + 5) = 148

⇒ 6x + 10 = 148

⇒ 6x = 148 – 10

⇒ 6x = 138

⇒ x = 138/6

⇒ x = 23

∴ Breadth of rectangle = 23 m

Length of the rectangle = 2x + 5 = (2 × 23) + 5

= 46 + 5 = 51 m

Check:

Length = 51 m, Breadth = 23 m

Perimeter = 2(l + b)

= 2(51 + 23)

= 2(74)

= 148 m

Hence Verified.