InterviewSolution
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InterviewSolution
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The length of a rubber cord is `l_(1)` m when the tension is 4 N and `l_(2)` m when the tension is 6 N.The length when the tension is 9 N, isA. `(2.5l_(2) - 1.5l_(1))m`B. `(6l_(2)- 1.5l_(1))m`C. `(3l_(1) - l_(2))m`D. `(3.5l_(2) =- 2.5l_(1))m` |
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Answer» Correct Answer - A Let the original unstrectched length be l. `therefore Y=(T)/(A)(l)/(Deltal)` Now `Y =(4)/(A)(l)/((l_(1)-l))=(6)/(A)(l)/((l_(2) -l)) =(9)/(A)(l)/((l_(3)-l))` `therefore 4(l_(3)-l) = 9(l_(1)-l) or 4l_(3)+ 5l = 9l_(1)" "…..(i)` Again, `6(l_(3)-l) =9(l_(2) -l) or 2l_(3) + l = 3l_(2)" "...(ii)` To obtain `l_(3)`,solve (i) and (ii) simultaneously. `therefore l_(3) = (2.5l_(2) - 1.2l_(1))m` |
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