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Two parallel and opposite forces each 5000 N are applied tangentially to the upper and lower faces of a cubical metal block of side 25 cm. the angle of shear is (The shear modulus of the metal is 80 Gpa)A. `10^(-4) rad`B. `10^(-5) rad`C. `10^(-6) rad`D. `10^(-7) rad` |
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Answer» Correct Answer - C Here, F = 5000 N `L = 25 cm = 25 xx 10^(-2)m` `A= (25xx 10^(-2)m)^(2) = 625 xx 10^(-4)m^(2)` `eta = 80 GPa = 80xx 10^(9) Pa` Angle of shear, `theta =(F)/(A eta) = (5000)/(625 xx 10^(-4)xx80xx 10^(9)) = 10^(-6)rad` |
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