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The length of a rubber cord is l_1 metres when the tension in it is 4N and l_2metres when the tension is 5N. Then the length in meters when the tension is 9 N is

Answer» <html><body><p></p>Solution :Let <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> be the original length and `l_3`be the length of the wire when the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> is 9N.<br/>` rArr (l_1 - l) prop 4......(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>), (l_2-l) prop 5........(2)` <br/>`(l_3 - l) prop 9...........(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/>From (1) and (2) `(l_1- l)/(l_2 - l) = 4/5 rArr 5l_1- 5l= 4l_2 - 4l` <br/>`l = 5l_1 - 4l_2`...(4)<br/>From (1) and (3) `(l_1 - l)/(l_3 - l) = 4/9 rArr (l_1 - (5l_2 - 4l_2))/(l_3 - (5l_1 - 4l_2)) = 4/9` <br/>`rArr (l_2 - 5l_1 + 4l_2)/(l_3 - 5l_1 + 4l_2) = 4/9 rArr (4l_2 - 4l_1)/(l_3 - 5l_1 + 4l_2) = 4/9` <br/>` rArr 36l_2 - 36l_1 = 4l_3 = 20l_2 + 16l_2` <br/>` 20l_2 - 16l_1= 4l_3 `<br/>`l_3 = 5l_2 - 4l_1`</body></html>


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