1.

The length of a second's pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on surface of planet X such that the acceleration of the planet X is n time greater than the Earth is

Answer»

0.9n
`(0.9)/(N)m`
`0.9n^(2)m`
`(0.9)/(n^(2))`

ANSWER :A


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