The length of a second's pendulum on the surface of the Earth is 0.9m. The length of the same pendulum of surface of planet X such that the acceleration of planet X is n times greater than the Earth is :

The length of a second's pendulum on the surface of the Earth is 0.9m.

1.	The length of a second's pendulum on the surface of the Earth is 0.9m. The length of the same pendulum of surface of planet X such that the acceleration of planet X is n times greater than the Earth is :
Answer» `0.9 N` `(0.9)/(n)m` `0.9 n^(2)m` `(0.9)/(n^(2))` Solution :`T= 2pi SQRT((l)/(G)),` `l=0.9m, T = 2pi sqrt((l_(x))/(g_(x)))` `g_(x)=NG` `l_(x)=0.9 n`