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The length of a second's pendulum on the surface of earth is 1 m. What will be its length on the surface of the moon? |
Answer» T = 2π√{l/g} In both the cases, T is the same l ∝ g. On the moon, the value of acceleration due to gravity is 1/6th of that on the surface of earth. So length of the second's pendulum is 1/6m. |
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