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The length of a seconds pendulum is decreased by 1%. What is the gain or loss in time per day? |
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Answer» Solution :`T PROP sqrtl,T_2//T_1=sqrt(l_2//l_1)T_2//2=sqrt(0.99l//l)=0.9949.T_2 =1.9898` Decrease in period = 2 - 1.9898 = 0.0102 s. GAIN in one DAY `= 0.0102 xx24xx60xx60//2 = 440.64 s`. |
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