The length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time period of the pendulum of increased length is…………

The length of a simple pendulum executing simple harmonic motion is in

1.	The length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time period of the pendulum of increased length is…………
Answer» `42%` `10%` `11%` `21%` SOLUTION :In `T= 2pi sqrt((l)/(m)), 2pi` and g are constant, `T propto sqrt(l)` `therefore (T_2)/(T_1)= sqrt((l_2)/(l_2))` `= sqrt((1.21 l_(1))/(l_1))= sqrt(1.21)= 1.1` Hence, percentage INCREASE in the TIME period `=(T_(2)-T_(1))/(T_1)xx 100` `=(1.1-1.0)xx 100` `= 10%`.