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The length of a simple pendulum is increased by 44%. The percentage increase in its time period will beA. 0.44B. `sqrt(44) %`C. 0.2D. 0.1 |
Answer» Correct Answer - C `(T_(2))/(T_(1))=sqrt(1.44)=(T_(2))/(T_(1))=1.20` `(T_(2)-T_(1))/(T_(1))=0.20 therefore (T_(2)-T_(1))/(T_(1))%=20%` |
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