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The length of a wire is increased by `1 mm` on the application of a given load. If a wire of the same material, but of length and radius twice that of the first, on application of the same load, extension isA. 2 mmB. 0.5 mmC. 4 mmD. 0.25 mm |
Answer» Correct Answer - B `Y=(F)/(pi r^(2)) xx (L)/(l_(1))` `therefore l_(1)=(FL_(1))/(pi r_(1)^(2)y) and l_(2)=(FL_(2))/(pi r_(2)^(2)y)` `(l_(2))/(l_(1))=(L_(2))/(L_(1)) xx (r_(1)^(2))/(r_(2)^(2))` |
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