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The length of a wire `l_(1)` when tension is 4 N and `l_(2)` when the tension is 5 N. Then its original length would beA. `9l_(1)-8l_(2)`B. `5l_(1)+4l_(2)`C. `5l_(1)-4l_(2)`D. `9l_(2)-8l_(1)` |
Answer» Correct Answer - B `L=(T_(2)l_(1)-T_(1)l_(2))/(T_(2)-T_(1))` `=(5l_(1)-4l_(2))/(5-4)=5l_(1)-4l_(2)`. |
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