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The length of a wire of a potentiometer is 100 cm, and the e.m.f. of its standard cell is E volt. It is employed to measure the e.m.f. of a battery whose internal resistance is `0.5 Omega`. If the balance point is obtained at I = 30 cm from the positive end, the e.m.f. of the battery is . where i is the current in the potentiometer wire.A. `(30E)/(100)`B. `(30E)/(100.5)`C. `(30E)/((100-0.5))`D. `(30(E-0.5i))/(100),(30(E-0.5))/(100)` where I is the current in the potentiometer

Answer» Correct Answer - A


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