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The length of alike metals produced by a hardware store is approximated by a normal distribution model having a mean of 7 cm and a standard deviation of 0.35 cm. Find the probability that the length of a randomly chosen metal is between 5.36 and 6.14 cm?(a) 0.562(b) 0.2029(c) 3.765(d) 1.576I got this question by my school teacher while I was bunking the class.This interesting question is from Probability Distribution topic in portion Discrete Probability of Discrete Mathematics

Answer»

The correct answer is (b) 0.2029

The best explanation: Let L be the random variable that represents the length of the COMPONENT. It has a mean of 7 CM and a standard deviation of 0.35 cm. To FIND P( 5.36 < X < 6.14). For x = 5.36, z = \(\frac{5.36 – 6}{0.35}\) = -1.82. For x = 6.14, z = \(\frac{6.14 – 6}{0.35}\) = 0.4 ⇒P(5.36 < x < 6.14) = P( -1.82 < z < 0.4) = 0.2029.



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