The length of the common chord of the two circles `x^2+y^2-4y=0` and ` – InterviewSolution

1.	The length of the common chord of the two circles `x^2+y^2-4y=0` and `x^2+y^2-8x-4y+11=0` is
Answer» `x^2+(y-2)^2=4 -(1)` `(x-4)^2+(y-2)^2=9 -(2)` from diagram `CC_1=4` area of `/_ACC_1=sqrt((9/2)(5/2)(3/2)(1/2))` =`sqrt(135)/4` area can also be find by=`1/2ADCC_1` so, it can be said that `sqrt(135)/4=1/2AD*4` AD=`sqrt135/8` length of chord=2AD=`sqrt135/4`

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