The length of the compound microscope is `14 cm.` The magnifying power for relaxed eye is `25`. If the focal length of eye lens is `5 cm`, then the object distance for objective lens will beA. 1.8 cmB. 1.5 cmC. 2.1 cmD. 2.4 cm

The length of the compound microscope is `14 cm.` The magnifying power

1.	The length of the compound microscope is `14 cm.` The magnifying power for relaxed eye is `25`. If the focal length of eye lens is `5 cm`, then the object distance for objective lens will beA. 1.8 cmB. 1.5 cmC. 2.1 cmD. 2.4 cm
Answer» Correct Answer - A Length of compound microscope, `L_(oo)=v_(o)+f_(e )rArr 14 v_(o)+5` `therefore " " v_(o)=9 cm` Mgnifying power of microscope for relaxed eye `M=(v_(o))/(u_(o)).(D)/(f_(e ))` or `25=(9)/(u_(o)).(25)/(5)` or distant of object, `u_(o)=(9)/(5)=1.8 cm`

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The length of the compound microscope is `14 cm.` The magnifying power for relaxed eye is `25`. If the focal length of eye lens is `5 cm`, then the object distance for objective lens will beA. 1.8 cmB. 1.5 cmC. 2.1 cmD. 2.4 cm

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