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The length of the resistance wire is increased by `10%`. What is the corresponding change in the resistance of wire?A. `10%`B. `25%`C. `21%`D. `9%` |
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Answer» Correct Answer - C (c ) `(R_(1))/(R_(2)) = ((l_(1))/(l_(2))^(2))`, If `I_(1) = 100` then `l_(2) = 110` `implies (R_(1))/(R_(2)) = ((100)/(110))^(2) implies R_(2) = 1.21 R_(1)` `%` change `(R_(2) - R_(1))/(R_(1)) xx 100 = 21 %` |
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