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The length of the tangent from (0, 0) to the circle `2(x^(2)+y^(2))+x-y+5=0`, isA. `sqrt(5)`B. `sqrt(5)//2`C. `sqrt(2)`D. `sqrt(5//2)` |
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Answer» Correct Answer - D The equation of the circle can be written as `x^(2)+y^(2)+(1)/(2)x-(1)/(2)y+(5)/(2)=0` Let l be the length of tangent drawn from (0, 0) to the given circle. Then, `l=sqrt(S_(1))=sqrt(0+0+0-0+(5)/(2))=sqrt((5)/(2))` |
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