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The length of the wire shown in the figure between the pulleys is 1.5m and its mass is 12.0g. The frequency of vibration with which the wire vibrates in three loops forming antinode at the mid point of the wire is - (Take `g=9.8 m//s^2`) A. 210 HzB. 140 HzC. 70HzD. none of these |
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Answer» `lambda=1m ` `v=sqrt((9xx9.8xx1.5)/(12xx10^(-3)))=105 m//s` `f=(105xx1)/1=105 Hz` |
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