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The length of two metallic rods at temperatures `theta` are `L_(A)` and `L_(B)` and their linear coefficient of expansion are `alpha_(A)` and `alpha_(B)` respectively. If the difference in their lengths is to remian constant at any temperature thenA. `L_(A)//L_(B)=alpha_(A)//alpha_(B)`B. `L_(A)//L_(B)=alpha_(B)//alpha_(A)`C. `alpha_(A)=alpha_(B)`D. `alpha_(A)alpha_(B)=1` |
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Answer» Correct Answer - B Change in `L_(A)`=change in `L_(B)` i.e. `DeltaL_(A)=DeltaL_(B)` `rArr alpha_(A) DeltaTL_(A)=alpha_(B)DeltaTL_(B)` or `alpha_(A) L_(A)=alpha_(B) L_(B)` |
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