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The length og two metal wire is l_(1) when the tension in it is F_(1) and l_(2) when the tension is F_(2) .then the original length of the wire is |
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Answer» Solution :Let I be the natural length of the wire. For the force` F_(1)` if elongation is `e_(1)` `e_(1)=(F_(1)l)/(AY) rArr Y=(F_(1)l)/(Ae_(1))` Similarly for the force `F_(2)`, if elongation is `e_(2)` `e_(2)=(F_(2)l)/(AY)= rArr Y=(F_(2)l)/(Ae_(2)), l_(2)=l+e_(1) and l_(2)=l+e_(2)` `Y=(F_(1)l)/(A(l_(1)-l))=(F_(2)l)/(A(l_(2)-l))= F_(1)(l_(1)-l)=F_(2)(l_(1)-l) and F_(1)l_(2)-F_(1)=F_(2)l_(1)-F_(2)l` `(F_(2)-F_(1))=l=l_(1)F_(2)-l_(2)F_(1) or l=(l_(1)F_(2)-l_(2)F_(1))/((F_(2)-F_(1)))` |
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