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The lengths of the parallel sides of a trapezium are (x + 9) cm and (2xthe distance between them is (x + 4) cm. If its area is 540 cm, find x.m aICDioten |
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Answer» 16 One parallel side=(x+9)cmOther parallel side=(2x-3)cmDistance between the parallel sides=(x+4)cmArea of the trapezium=540cm^2 Area of a trapezium=1/2×sum of parallel sides×distance between them =(x+9+2x-3)(x+4)=540×2 = (3x+6)(x+4)=540×2 = 3x^2+18x+24=1080 = 3x^2+18x=1080-24 =3x^2+18x=1056 = 3x^2+18x-1056=0 = x^2+18x-352=0 Solve this quadratic equation The positive one will be your answer. |
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