1.

The lengths of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of this triangle is(a) 24(b) 72(c) 48(d) 144

Answer»

(b) 72 cm2

Here sm\(\frac{9+12+15}{2}\) = 18 cm, where lengths of medians are m1 = 9 cm, m2 = 12 cm, m3 = 15 cm.

∴ Area of triangle = \(\frac{4}{3}\sqrt{18(18-9)(18-12)(18-15)}\) cm2

\(\frac{4}{3}\sqrt{18\times9\times6\times3}\) cm\(\frac{4}{3}\) x 9 x 6 cm= 72 cm2.



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