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The lengths of two rods are recorded as l1 = 25.2 ± 0.1 cm. and l2 = 16.8 ± 0.1 cm. Find the sum of the lengths of the two rods with the limits of error. |
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Answer» Here, l1 + l2 = (25.2 ± 0.1) + (16.8 ± 0.1) = 42.0 ± 0.2 cm. |
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