The lergth of the minute hand of a clock is 7 pm. Find the area swept

1.	The lergth of the minute hand of a clock is 7 pm. Find the area swept by the minutehand from 6.00 pm to 6.10 pm.
Answer» In 60 min, the minute hand sweeps 360 degrees. Hence in 10 min, the minute hand sweeps 10360/60 = 60 degrees. The area swept will be the area of the sector formed by the minute hand. Therefore, Area swept = Area of sector = theta / 360 pi radius^2 = 60 / 360 * 22/7 * 7^2 = 25.665 cm^2

The lergth of the minute hand of a clock is 7 pm. Find the area swept by the minutehand from 6.00 pm to 6.10 pm.

Answer»

In 60 min, the minute hand sweeps 360 degrees.

Hence in 10 min, the minute hand sweeps 10*360/60 = 60 degrees.

The area swept will be the area of the sector formed by the minute hand.

Therefore, Area swept = Area of sector

= theta / 360 * pi radius^2

= 60 / 360 * 22/7 * 7^2

= 25.665 cm^2