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The Li^(2+) ion is a hydrogen like ion that can be described by the Bohr model. Calculate the Bohr radius of the thired orbital and calculate the energy of an electron in 4^(th) orbital. |
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Answer» SOLUTION :`r_(n) = ((0.529)n^2)/(z) Å ""E_(n) = (-13.6 (z^2))/(n^2) ev "atom"^(-1)` for `Li^(2+) z = 3` Bohr RADIUS for the THIRD orbit `(r_3)` `=((0.529)(3)^2)/(3)` `= 0.529 xx 3` `= 1.587 Å` Energy of an electron in the fourth orbit `(E_4) = (-13.6(3)^2)/((4)^2)` `= -7.65 eV atom^(-1)`. |
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