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The Li^(2+) ion is a hydrogen like ion that can BE DESCRIBED BY THE Bohr model.Calculate the Bohr radius of the third orbit and calculate the energy of an electron in 4^(th) orbit. |
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Answer» Solution :`Li^(2+)`=HYDROGEN LIKE ion. Bohr radius of the third orbit =`r_3`=? `r_3=((0.529)xx3^(2)N^(2))/(Z)`A where n=shell number,Z= atomic number. `r_3=(0.529xx3^(2))/(2)`[because for lithliumZ=3,n=3] `=(0529xx9)/(3)``r_3+1.587A` `E_n=((-13.6)Z^(2))/(n^(2))eV at OM^(-1)` `E_4`=Energy of the fourth orbit=? `E_4=((-13.6)Z^(2))/(4^(2))` `=(-13.6xx9)/(16)=-7.65eVatom^(-1)` `E_4=-7.65eVatom^(-1)` |
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