1.

The Li^(2+) ion is a hydrogen like ion that can BE DESCRIBED BY THE Bohr model.Calculate the Bohr radius of the third orbit and calculate the energy of an electron in 4^(th) orbit.

Answer»

Solution :`Li^(2+)`=HYDROGEN LIKE ion.
Bohr radius of the third orbit =`r_3`=?
`r_3=((0.529)xx3^(2)N^(2))/(Z)`A where n=shell number,Z= atomic number.
`r_3=(0.529xx3^(2))/(2)`[because for lithliumZ=3,n=3]
`=(0529xx9)/(3)``r_3+1.587A`
`E_n=((-13.6)Z^(2))/(n^(2))eV at OM^(-1)`
`E_4`=Energy of the fourth orbit=?
`E_4=((-13.6)Z^(2))/(4^(2))`
`=(-13.6xx9)/(16)=-7.65eVatom^(-1)`
`E_4=-7.65eVatom^(-1)`


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