The lie x−b+λy=0 cuts the parabola y2=4ax at P(t1) and Q(t2). If b� – InterviewSolution

1.	The lie x−b+λy=0 cuts the parabola y2=4ax at P(t1) and Q(t2). If b∈[2a,4a] and λ∈R, then the value(s) [t1t2] is/are (where [.] repreasents the greatest integer function and t1,t2 are parametic points)
Answer» The lie $x - b + λ y = 0$ cuts the parabola $y^{2} = 4 a x$ at $P (t_{1})$ and $Q (t_{2})$ . If $b \in [2 a, 4 a]$ and $λ \in R$ , then the value(s) $[t_{1} t_{2}]$ is/are (where $[.]$ repreasents the greatest integer function and $t_{1}, t_{2}$ are parametic points)

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