1.

The light-blue glow given off by mercury street-lamps has a wavelength of `436 nm`. What is its frequency in hertz? Strategy: We given a wavelength and need to find the frequency. Wavelength and frequency are inversely related by the equation `lambdav = c`, which can be solved for `v`. Remember to convert `lambda` from nanometers to meters.

Answer» According to Eq. we have
`v = (c )/(lambda) = ((3.00xx10^(8)(m)/(s)))/((436nm)((10^(-9)m)/(1nm)))`
`6.88xx10^(14)s^(-1)`
`= 6.88 xx 10^(14) Hz`


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