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The limit of resolution of microscope, if the numerical aperture of microscope is `0.12`, and the wavelength of light used is 600 nm, isA. `0.25xx10^(-7)m`B. `2.5xx10^(-7)m`C. `25xx10^(-7)m`D. `250xx10^(-7)m` |
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Answer» Correct Answer - C `25xx10^(-7)m` `mu sin theta=0.12, lamda =6000Å, dimplies` `d=(lamda)/(2 mu sin theta)` `=(6xx10^(-7))/(2xx0.12)` `=(6xx10^(-7))/(0.24)` `d= 25xx10^(-7)m.` |
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