1.

The limit of resolution of microscope, if the numerical aperture of microscope is `0.12`, and the wavelength of light used is 600 nm, isA. `0.25xx10^(-7)m`B. `2.5xx10^(-7)m`C. `25xx10^(-7)m`D. `250xx10^(-7)m`

Answer» Correct Answer - C
`25xx10^(-7)m`
`mu sin theta=0.12, lamda =6000Å, dimplies`
`d=(lamda)/(2 mu sin theta)`
`=(6xx10^(-7))/(2xx0.12)`
`=(6xx10^(-7))/(0.24)`
`d= 25xx10^(-7)m.`


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