1.

The limiting density of hydrogen bromide is 3.6108 at 0^(@)C. The exact atomic weight ofbromine is (At. wt. of H = 1.008)

Answer»

80.92
79.92
89.29
79.29

Solution :This can be calculated by limiting density method which is BASED on the fact that at LIMIT of zero pressure the ideal gas equation hecomes exact for all gases i.e.,
PV=nRT
Molecular weight of HBr on this BASIS is
`M=RT(p/P)_(Pto0)`
`M=0.0821xx273.15xx3.6108[0^(@)C=273.15K]=80.93`
`therefore` 80.93 = atomic weight of hydrogen+ atomic weight of bromine
=1.008 + atomic weight of bromine
or atomic weight ofbromine= 80.93 - 1.008 = 79.92


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