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The limiting molar conductivities of HCl, `CH_(3)COONa` and NaCl are respectively 425, 90 and 250 mho `cm^(2)mol^(-1)` at `25^(@)C`.t he molar conductivity of 0.1 M `CH_(3)COOH` solution is 7.8 mho `cm^(2)mol^(-1)` at the same temperature. The degree of dissociation of 0.1 M acetic acid solution at the same temperature isA. `0.10`B. `0.02`C. `0.15`D. `0.03` |
Answer» Correct Answer - B `wedge_(CH_(3)COOH)^(@)=wedge_(CH_(3)COONa)^(@)+wedge_(HCl)^(@)-wedge_(NaCl)^(@)` `=90+425-125=390" mho "cm^(2)mol^(-1)` `alpha=(wedge_(m)^(@))/(wedge_(m)^(@))=(7.8)/(390)=.02` |
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