The line 2x+3y+4=0 cut the circle x2+y2+ax+by+c=0 at P and Q. The line x−3y+2=0 cut the circle x2+y2+a′x+b′y+c′ at R and S. If P,Q,R and S are concyclic and value of ∣∣∣∣a−a′b−b′c−c′2341−32∣∣∣∣=k(abc)(a′b′c′), then k=

The line 2x+3y+4=0 cut the circle x2+y2+ax+by+c=0 at P and Q. The line

1.	The line 2x+3y+4=0 cut the circle x2+y2+ax+by+c=0 at P and Q. The line x−3y+2=0 cut the circle x2+y2+a′x+b′y+c′ at R and S. If P,Q,R and S are concyclic and value of ∣∣∣∣a−a′b−b′c−c′2341−32∣∣∣∣=k(abc)(a′b′c′), then k=
Answer» The line $2 x + 3 y + 4 = 0$ cut the circle $x^{2} + y^{2} + a x + b y + c = 0$ at $P$ and $Q$ . The line $x - 3 y + 2 = 0$ cut the circle $x^{2} + y^{2} + a^{'} x + b^{'} y + c^{'}$ at $R$ and $S$ . If $P, Q, R$ and $S$ are concyclic and value of $∣ ∣∣ ∣ \begin{matrix} a - a^{'} & b - b^{'} & c - c^{'} 2 & 3 & 4 1 & - 3 & 2 \end{matrix} ∣ ∣∣ ∣ = k (a b c) (a^{'} b^{'} c^{'})$ , then $k =$