The line `(k + 1)x + ky-2k^2-2=0` passes through a point regardless of the value k. Which of the following is the line with slope 2 passing through the point?

The line `(k + 1)x + ky-2k^2-2=0` passes through a point regardless of

1.	The line `(k + 1)x + ky-2k^2-2=0` passes through a point regardless of the value k. Which of the following is the line with slope 2 passing through the point?
Answer» the line given is `(k+1)^2x +ky-2k^2 -2 = 0` as `y=mx+c` `ky= -(k+1)^2x+ (2k^2+2)` `y= -(k+1)^2x/k + (2k^2+2)/k` where `m= -(k+1)^2/k = 2` `-(k+1)^2 = 2k` `-(k^2+2k+1) = 2k` `-k^2 -2k-2k-2=0` `k^2 +4k+1= 0` `k= (-4+-sqrt(16-41))/2` `k= -2 +- sqrt 3` c is given `c=(2k^2 +2)/k= 2(k+1/k)` for `k=-2 +sqrt3` `c = 2(-2 + sqrt3 + (1/(-2+sqrt3))(-2-sqrt3)/(-2 - sqrt3)` `=2[-2 + sqrt3 + (-2 - sqrt3)]` `= 2(-4) = -8` for `k=-2 -sqrt3` `c = 2(-2 - sqrt3 + (1/(-2-sqrt3))*(-2-+qrt3)/(-2 + sqrt3)` `=2[-2 - sqrt3 + (-2 + sqrt3)]` `= 2(-4) = -8`equation of line is `y= 2x-8` option A is correct

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The line `(k + 1)x + ky-2k^2-2=0` passes through a point regardless of the value k. Which of the following is the line with slope 2 passing through the point?

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