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The line segment joining the mid - points of any two sides of a triangle is parallel to the third side and equal to half of it. In the given figure, the side AC of ΔABC is produced of E such that CE=12AC. If D is the mid - points of BC and ED produced meets AB at F and CP, DQ are drawn parallel to BA, then FD = |
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Answer» The line segment joining the mid - points of any two sides of a triangle is parallel to the third side and equal to half of it. |
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