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The line through P (5, 3) intersects y-axis at Q.(i) write the slope of the line(ii) write the equation of the line(iii) Find the co-ordinates of Q. |
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Answer» (i) The equation of the y-axis is x = 0 Given that the required line through P (5, 3) Intersects the y-axis at Q and the angle of inclination is 45° Therefore slope of the line PQ = tan 45° = 1 (ii) The equation of a line passing through the point A(x1, y1) with slope ‘m’ is y – y1 = m (x – x1) Therefore, the equation of the line passing through the point P (5, 3) with slope 1 is y -3 = 1 ×(x – 5) ⇒ y – 3 = x – 5 ⇒ x – y = 2 (iii) From subpart (ii), the equation of the line PQ Is x – y = 2 Given that the line intersects with the y – axis, x = 0 Thus, substituting x = 0 in the equation x – y = 2 We have, 0 – y = 2 ⇒ y = − 2 Thus, the coordinates point of intersection Q Are q(0, −2) |
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