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The line `(x+1)/(-10)=(y+3)/(-1)=(z-4)/1 and (x+10)/(-1)=(y+1)/(-3) =(z-1)/(4)` interest at the point.A. (11,-4,5)B. (-11,-4,5)C. (11,4,-5)D. (-11,-4,-5) |
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Answer» Correct Answer - B Let `(x+1)/(-10)=(y+3)/(-1)=(z-4)/(1)=lambda_(1)` `and (x+10)/(-1)=(y+1)/(-3)=(z-1)/(4)=lambda_(2)` `"Then", (-10lambda_(1)-1-lambda_(2)-3,lambda_(1)+4)` and `(-lambda_(2)-10,-3lambda_1-1, 4lambda_(2)+1)` are identical. `-10lambda_(1)-1=-lambda_(2)-10,-lambda,-3=-3lambda_2-1` and `lambda_(1)+4=4lambda_(2)+1` `Rightarrow -10lambda_(1)+lambda_(2)=-9-lambda_(1)+3lambda_(2)=2` `lambda_(1)-4lamda2=-3` On solving, we get `lambda_(1)=lambda_(2)=1` Intersection points is `(-10xx1-1, -1-3,1+4)i.e, (-11,-4,5)` On solving, we get `x=-11, y=-4 and z=5`. |
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